11. x - y = 12 and x · y = 108 are given. Find x + y.A) +20 B) +24 C) +28 D) +30 E) +32. Created by danesha777ali. matematika-ru

Ответ:-18+30=12х=-18у=30Пошаговое объяснение:x-y=12x*y=108x=y+12y=12-xx1=6 ❌❌❌x2=-186-у=12-у=6у=-6-18-у=12-у=12+18у=-30-18-(-30)=12

11. x - y = 12 and x · y = 108 are given. Find x + y.A) +20 B) +24 C) +28 D) +30...

danesha777ali @danesha777ali

July 2022 1 1 Report

11. x - y = 12 and x · y = 108 are given. Find x + y.
A) +20 B) +24 C) +28 D) +30 E) +32

Answers & Comments

Bekzatgguru

Ответ:

-18+30=12

х=-18

у=30

Пошаговое объяснение:

x-y=12

x*y=108

x=y+12

y=12-x

$(y + 12)y = 108 \\ y {}^{2} + 12y - 108 = 0 \\ d = 12 {}^{2} + 4 \times 108 = 576 \\ x 1= \frac{ - 12 + 24}{2} = 6 \\ x2 = \frac{ - 12 - 24}{2} = - 18$

x1=6 ❌❌❌

x2=-18

6-у=12

-у=6

у=-6

-18-у=12

-у=12+18

у=-30

-18-(-30)=12

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