Ответ:

Объяснение:

1) (x⁻¹·y⁻²)⁻²=x^(-1·(-2)) ·y^(-2·(-2))=x²y⁴

2) (1/2 ·a⁻³b³)⁻²=2²a^(-3·(-2)) ·b^(3·(-2))=4a⁶b⁻⁶=(4a⁶)/b⁶

3) (0,25m⁻²n²)⁻³=(1/4)⁻³·m^(-2·(-3)) ·n^(2·(-3))=4³m⁶n⁻⁶=(64m⁶)/n⁶

4) (a³·b⁻¹)²=a^(3·2) ·b^(-1·2)=a⁶b⁻²=a⁶/b²

5) (-3p³q⁻¹)²=(-3)²p^(3·2) ·q^(-1·2)=9p⁶q⁻²=(9p⁶)/q²

6) (1/3 ·x⁻³y²)³=(1/3)³·x^(-3·3) ·y^(2·3)=1/27 ·x⁻⁹y⁶=y⁶/(27x⁹)