Verified answer

[tex]\displaystyle\bf\\g(x)=\frac{2-x}{2+x} \\\\x=-1\\\\g(-1)=\frac{2-(-1)}{2+(-1)} =\frac{2+1}{2-1} =\frac{3}{1} =3\\\\\\\boxed{g(-1)=3}\\\\g(x)=-5\\\\-5=\frac{2-x}{2+x} \\\\\\2-x=-5\cdot(2+x)\\\\2-x=-10-5x\\\\-x+5x=-10-2\\\\4x=-12\\\\\boxed{x=-3}[/tex]