2Al+3H2SO4=Al2(SO4)3+3H2
M(Al)=27г/моль
n=m/M
n(Al)=112/27=4,15
n(Al):n(H2)=2:1
n(H2)=4,15*3/2=6,225моль
V=n*Vm
V=6,225*22,4=139,44л
Ответ:139,44л
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Verified answer
2Al+3H2SO4=Al2(SO4)3+3H2
M(Al)=27г/моль
n=m/M
n(Al)=112/27=4,15
n(Al):n(H2)=2:1
n(H2)=4,15*3/2=6,225моль
V=n*Vm
V=6,225*22,4=139,44л
Ответ:139,44л