n(H2) = N(H2) : Na = 12.04×10²³ : 6,02×10²³ = 2 моль
m(H2) = n(H2) × M(H2) = 2 × 2 = 4 г
V(H2) = n(H2) × Vm = 2 × 22,4 = 44,8 л
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n(H2) = N(H2) : Na = 12.04×10²³ : 6,02×10²³ = 2 моль
m(H2) = n(H2) × M(H2) = 2 × 2 = 4 г
V(H2) = n(H2) × Vm = 2 × 22,4 = 44,8 л