Ответ:
(cosπ/12-sinπ/12)(cosπ/12+sinπ/12)=
=cos²π/12-sin²π/12=cos(2*π/12)=cosπ/6=√3/2
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Ответ:
(cosπ/12-sinπ/12)(cosπ/12+sinπ/12)=
=cos²π/12-sin²π/12=cos(2*π/12)=cosπ/6=√3/2