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ARTwoR
@ARTwoR
August 2022
1
28
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1)Найдите значение выражений
√(48)-√(192)*sin(^2)π/12
2)Решите уравнение
√x(^2)+5=7-2x
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Answers & Comments
abieva
1) √(48)-√(192)*sin(^2)π/12=√48(1-2sin²π/12) = 4√3(cos(π/6)) = 4√3*√3/2=2*3
=6
2)
√x(^2)+5=7-2x
х+5=7-2х
3х=2
х=2/3
1 votes
Thanks 1
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Answers & Comments
2) √x(^2)+5=7-2x
х+5=7-2х
3х=2
х=2/3