Ответ:
1)
-6(2x+6y)=-2x+4;
-12x-36y=-2x+4;
-10x-36y-4=0.
2)
[tex]8-2\frac{2}{7}*2\frac{11}{12}=8-\frac{16}{7}*\frac{35}{12}=8-\frac{4}{1} *\frac{5}{3}=8-\frac{20}{3}=7\frac{3}{3}-6\frac{2}{3} =1\frac{1}{3}[/tex]
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Answers & Comments
Ответ:
1)
-6(2x+6y)=-2x+4;
-12x-36y=-2x+4;
-10x-36y-4=0.
2)
[tex]8-2\frac{2}{7}*2\frac{11}{12}=8-\frac{16}{7}*\frac{35}{12}=8-\frac{4}{1} *\frac{5}{3}=8-\frac{20}{3}=7\frac{3}{3}-6\frac{2}{3} =1\frac{1}{3}[/tex]