(9 1/3*9 1/4/12 корень 9)^3. Created by KikoKuma. algebra-ru

12 корень 9)^3...

DariosI

Verified answer

$\frac{9^{ \frac{1}{3}}*9^{ \frac{1}{4}} }{ \sqrt[12]{9} } = \frac{9^{ \frac{1}{3}+ \frac{1}{4}} }{ 9^{ \frac{1}{12}} } = \frac{9^{ \frac{7}{12}} }{ 9^{ \frac{1}{12}} } =9^{ \frac{7}{12}- \frac{1}{12} }=9^{ \frac{6}{12}}=9^{ \frac{1}{2}}= \sqrt{9}=3$

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Luluput

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$(( 9^{ \frac{1}{3} } * 9^{ \frac{1}{4} } )/ \sqrt[12]{9} ) ^{3} =(( 9^{ \frac{4+3}{12} }): 9^{ \frac{1}{12} } ) ^{3} =(9 ^{ \frac{7}{12} } :9 ^{ \frac{1}{12} } ) ^{3} =(9 ^{ \frac{7-1}{12} }) ^{3} =$

$=(9 ^{ \frac{6}{12} } ) ^{3} =(9 ^{ \frac{1}{2} } ) ^{3} =( \sqrt{9} ) ^{3} = 3^{3} =27$

Или в другой записи:

$( \frac{9 ^{ \frac{1}{3} }*9 ^{ \frac{1}{4} } }{ \sqrt[12]{9} } ) ^{3} =( \frac{9 \frac{4+3}{12} }{9 ^{ \frac{1}{12} } } ) ^{3} =( \frac{9 ^{ \frac{7}{12} } }{9 ^{ \frac{1}{12} } }) ^{3} =(9 ^{ \frac{7-1}{12} }) ^{3} =(9 ^{ \frac{6}{12} } ) ^{3} =(9 ^{ \frac{1}{2} }) ^{3} =$

$=( \sqrt{9} ) ^{3} = 3^{3} =27$

Условие в приложении.

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