Ответ:
В2О3
Объяснение:
Mr(B2O3) = 11*2 + 16*3 = 70
W(O) = Ar(O) *n / Mr(B2O3) *100% = 16*3 / 70 *100% = 68%
Mr(Li2O) = 7*2 + 16 = 30
W(O) = Ar(O) *n / Mr(Li2O) *100% = 16*1 / 30 *100% = 53%
Mr(N2O) = 14*2 + 16 = 44
W(O) = Ar(O) *n / Mr(N2O) *100% = 16*1 / 44 *100% = 36%
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Ответ:
В2О3
Объяснение:
Mr(B2O3) = 11*2 + 16*3 = 70
W(O) = Ar(O) *n / Mr(B2O3) *100% = 16*3 / 70 *100% = 68%
Mr(Li2O) = 7*2 + 16 = 30
W(O) = Ar(O) *n / Mr(Li2O) *100% = 16*1 / 30 *100% = 53%
Mr(N2O) = 14*2 + 16 = 44
W(O) = Ar(O) *n / Mr(N2O) *100% = 16*1 / 44 *100% = 36%