m(CH3COOH)=120г
Решение :
М(CH3COOH)=2*12+2*16*4*1=60 г/моль
n(CH3COOH)=m/M=120/60=2 моля
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m(CH3COOH)=120г
Решение :
М(CH3COOH)=2*12+2*16*4*1=60 г/моль
n(CH3COOH)=m/M=120/60=2 моля