121...

Рrogrammist @Рrogrammist

July 2022 1 13 Report

квадратный корень из:
1/25
36/49
16/121

Answers & Comments

maymr

Verified answer

$\tt\displaystyle \sqrt{\frac{1}{25} } =\sqrt{\frac{1^2}{5^2} } =\sqrt{(\frac{1}{5})^2 }= \bold { \frac{1}{5} } \\\\\\\sqrt{\frac{36}{49} }=\sqrt{\frac{6^2}{7^2} } =\sqrt{(\frac{6}{7})^2 }=\bold {\frac{6}{7} } \\\\\\\sqrt{\frac{16}{121} } =\sqrt{\frac{4^2}{11^2} } =\sqrt{(\frac{4}{11} )^2} = \bold{ \frac{4}{11} }$

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