Сократите дробь: (-11х^2 + 10 + 17x)/121x^2 - 25. Created by Chemist13. algebra-ru

121x^2 - 25...

Okuma7 (-11х^2 + 10 + 17x)/121x^2 - 25
$-11 x^{2} +17x+10=0

D=289+440=729
 
x_{1} = \frac{-17-27}{-22} = \frac{-44}{-22}=2

 x_{2}= \frac{-17+27}{-22} =- \frac{10}{22} =- \frac{5}{11} 

-11x^{2} +17x+10=-11(x-2)(x+ \frac{5}{11} )=(x-2)(-11x-5)=

=-(x-2)(11x+5)



$ $- \frac{(x-2)(11x+5)}{(11x-5)(11x+5)} =- \frac{(x-2)}{(11x-5)} = \frac{2-x}{11x-5}$

1 votes Thanks 1

Shelkovaia

Verified answer

(-11x^2+17x+10)/(11x-5)*(11x+5)
(-11x^2+22x-5x+10)/(11x-5)*(11x+5)
(-11x*(x-2)-5(x-2))/(11x-5)*(11x+5)
((-11x-5)*(x-2))/(11x-5)*(11x+5)
(-(11x+5)*(x-2))/(11x-5)*(11x+5)
(-(x-2))/11-5
$-\frac{x-2}{11x-5}$

3 votes Thanks 2

Answers & Comments

Verified answer

121x^2 - 25...

kakoe slovosochetanie mozhno sostavit so slovom klyatvennyj oe aya

рекомендуемые вопросы

Helpful Links

Helpful Social