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yuliavinyukova
@yuliavinyukova
July 2022
1
19
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Помогите, оч срочно нужно
Упростите выражение
Sin(45+альфа) + cos(45+альфа) /sin(45+альфа) -cos(45+альфа)
Найти значение выражения
Sin^2*Π/13+cos^2*Π/13-(cos^2*Π/12-sin^2*Π/12)^2
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sedinalana
Verified answer
1
(sin45*cosa+cos45*sina+cos45*cosa-sin45*sina)/
(sin45*cosa+cos45*sina+cos45*cosa+sin45*sina)=
(√2/2cosa+√2/2sina+√2/2cosa-√2/2sina)/(√2/2cosa+√2/2sina+√2/2cosa+√2/2sina)=√2cosa√2(cosa+sina)=cosa/(cosa+sina)
2
sin²π/13+cos²π/13-(cos²π/12-sin²π/12)²=1-cos²π/6=sin²π/6=1/4
1 votes
Thanks 1
yuliavinyukova
Спасибо огромное :-*
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Answers & Comments
Verified answer
1(sin45*cosa+cos45*sina+cos45*cosa-sin45*sina)/
(sin45*cosa+cos45*sina+cos45*cosa+sin45*sina)=
(√2/2cosa+√2/2sina+√2/2cosa-√2/2sina)/(√2/2cosa+√2/2sina+√2/2cosa+√2/2sina)=√2cosa√2(cosa+sina)=cosa/(cosa+sina)
2
sin²π/13+cos²π/13-(cos²π/12-sin²π/12)²=1-cos²π/6=sin²π/6=1/4