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Efgefs
@Efgefs
August 2022
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Помогите пожалуйста найти tg a ,если cos a равен 5/12
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RizzenT
Cos^2 a + sin^2a = 1. sin^2a = 1-cos^2a= 1- (5/12)^2 =1- 25/144=144/144 -25/144 =119/144. sin a =sqrt(119)/12
tga= sina/cosa= sqrt(119)/12 *12/5= sqrt(119)/5 (sqrt-кв. корень)
ответ:tga=sqrt(119)/5
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Answers & Comments
tga= sina/cosa= sqrt(119)/12 *12/5= sqrt(119)/5 (sqrt-кв. корень)
ответ:tga=sqrt(119)/5