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ivanovaanyuta
@ivanovaanyuta
August 2021
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Найдите наибольшее целое число принадлежащее множеству решений неравенства: 0,2^x-2>(1/125)^20-3x
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nafanya2014
Verified answer
0,2=1/5
1/125=(1/5)³
(1/5)ˣ⁻²>((1/5)³)²⁰⁻³ˣ
(1/5)ˣ⁻²>(1/5)⁶⁰⁻⁹ˣ
x-2<60-9x;
x+9x<60+2
10x<62
x<6,2
x=6
2 votes
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Answers & Comments
Verified answer
0,2=1/51/125=(1/5)³
(1/5)ˣ⁻²>((1/5)³)²⁰⁻³ˣ
(1/5)ˣ⁻²>(1/5)⁶⁰⁻⁹ˣ
x-2<60-9x;
x+9x<60+2
10x<62
x<6,2
x=6