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pilulka1011
@pilulka1011
August 2022
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(0,2) в степени х в квадрате × 25 в степени 2х+1= 1/125
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rubilovalex
(5^-1)^x^2*(5^2)^2x+1=5^(-3); 5^(4x+2-x^2)=5^(-3); -x^2+4x+2= -3; -x^2+4x+2+3=0; -x^2+4x+5=0;D=16-4*(-1)*5=36; x1=(-4-6)/(-2), x2=(-4+6)/(-2). x1=5, x2= -1. Ответ: x1=5, x2= -1.
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