Сократить дробь: (202^2-108^2)*5^3n-5/125^n-1. Created by Morfeya. algebra-ru

125^n-1...

Morfeya @Morfeya

August 2021 1 50 Report

Сократить дробь: (202^2-108^2)*5^3n-5/125^n-1

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inblu

Verified answer

$\frac{(202^2-108^2)*5^{3n-5}}{125^{n-1}}=\frac{(202-108)(202+108)*5^{3n-5}}{(5^3)^{n-1}}=\frac{94*310*5^{3n-5}}{5^{3n-3}}= \frac{94*310}{5^{3n-3-3n+5}} \\ = \frac{94*310}{5^2}=\frac{94*310}{25}=1165.6$

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Answers & Comments

Verified answer

koren iz x koren iz y 3

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pomogite pozhalujsta kto drevnee kalmar gidra ili lancetnik

kakova svyaz uglevodov s drugimi organicheskimi soedineniyami v processe obmena ve

pomogite najti korni uravneniya na zadannom promezhutke ctg4x 1 0pi

pomogite pozhalujsta v hode termicheskogo razlozheniya nitrita ammoniya bylo poluche

b)...

2pi vtg a 2pi

najdite xesli izvestnochto chisla x 3koren iz 5xx16 yavlyayutsya posledovatelny

reshite sistemu uravnenij x12y 10 2y2x y5

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