очень срочно пожалуйста помогите решить
1)корень 100/2 корень 40
2) х в квадрате -6х+9/х в квадрате-3х(сократить)
3)корень 18+корень 64- 4 корень 2
4) 8а-40/4а в квадрате-100
5) 5а+30/ а в квадрате-36
6) 4х+20/ х в квадрате+10х+25
7) корень 49х-3корень4х+корень х
8)16а в квадрате +8а+1/12а+3
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Answers & Comments
1)![\frac{\sqrt{100}}{2\sqrt40}=\frac{10}{4\sqrt10}=\frac{\sqrt10}{4} \frac{\sqrt{100}}{2\sqrt40}=\frac{10}{4\sqrt10}=\frac{\sqrt10}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B100%7D%7D%7B2%5Csqrt40%7D%3D%5Cfrac%7B10%7D%7B4%5Csqrt10%7D%3D%5Cfrac%7B%5Csqrt10%7D%7B4%7D)
2)![\frac{x^{2}-6x+9}{x^{2}-3x}=\frac{(x-3)^{2}}{x(x-3)}=\frac{x-3}{x} \frac{x^{2}-6x+9}{x^{2}-3x}=\frac{(x-3)^{2}}{x(x-3)}=\frac{x-3}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-6x%2B9%7D%7Bx%5E%7B2%7D-3x%7D%3D%5Cfrac%7B%28x-3%29%5E%7B2%7D%7D%7Bx%28x-3%29%7D%3D%5Cfrac%7Bx-3%7D%7Bx%7D)
3)![\sqrt{18}+\sqrt{64}-4\sqrt{2}=3\sqrt{2}+8-4\sqrt{2}=8-\sqrt{2} \sqrt{18}+\sqrt{64}-4\sqrt{2}=3\sqrt{2}+8-4\sqrt{2}=8-\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B18%7D%2B%5Csqrt%7B64%7D-4%5Csqrt%7B2%7D%3D3%5Csqrt%7B2%7D%2B8-4%5Csqrt%7B2%7D%3D8-%5Csqrt%7B2%7D)
4)![\frac{8a-40}{4a^{2}-100}=\frac{8(a-5)}{4(a^{2}-25)}=\frac{2(a-5)}{(a-5)(a+5)}=\frac{2}{a+5} \frac{8a-40}{4a^{2}-100}=\frac{8(a-5)}{4(a^{2}-25)}=\frac{2(a-5)}{(a-5)(a+5)}=\frac{2}{a+5}](https://tex.z-dn.net/?f=%5Cfrac%7B8a-40%7D%7B4a%5E%7B2%7D-100%7D%3D%5Cfrac%7B8%28a-5%29%7D%7B4%28a%5E%7B2%7D-25%29%7D%3D%5Cfrac%7B2%28a-5%29%7D%7B%28a-5%29%28a%2B5%29%7D%3D%5Cfrac%7B2%7D%7Ba%2B5%7D)
5)![\frac{5a+30}{a^{2}-36}=\frac{5(a+6)}{(a-6)(a+6)}=\frac{5}{a-6} \frac{5a+30}{a^{2}-36}=\frac{5(a+6)}{(a-6)(a+6)}=\frac{5}{a-6}](https://tex.z-dn.net/?f=%5Cfrac%7B5a%2B30%7D%7Ba%5E%7B2%7D-36%7D%3D%5Cfrac%7B5%28a%2B6%29%7D%7B%28a-6%29%28a%2B6%29%7D%3D%5Cfrac%7B5%7D%7Ba-6%7D)
6)![\frac{4x+20}{x^{2}+10x+25}=\frac{4(x+5)}{(x+5)^{2}}=\frac{4}{x+5} \frac{4x+20}{x^{2}+10x+25}=\frac{4(x+5)}{(x+5)^{2}}=\frac{4}{x+5}](https://tex.z-dn.net/?f=%5Cfrac%7B4x%2B20%7D%7Bx%5E%7B2%7D%2B10x%2B25%7D%3D%5Cfrac%7B4%28x%2B5%29%7D%7B%28x%2B5%29%5E%7B2%7D%7D%3D%5Cfrac%7B4%7D%7Bx%2B5%7D)
7)![\sqrt{49x}-3\sqrt{4x}+\sqrt{x}=7\sqrt{x}-6\sqrt{x}+\sqrt{x}=2\sqrt{x} \sqrt{49x}-3\sqrt{4x}+\sqrt{x}=7\sqrt{x}-6\sqrt{x}+\sqrt{x}=2\sqrt{x}](https://tex.z-dn.net/?f=%5Csqrt%7B49x%7D-3%5Csqrt%7B4x%7D%2B%5Csqrt%7Bx%7D%3D7%5Csqrt%7Bx%7D-6%5Csqrt%7Bx%7D%2B%5Csqrt%7Bx%7D%3D2%5Csqrt%7Bx%7D)
8)![\frac{16a^{2}+8a+1}{12a+3}=\frac{(4a+1)^{2}}{3(4a+1)}=\frac{4a+1}{3} \frac{16a^{2}+8a+1}{12a+3}=\frac{(4a+1)^{2}}{3(4a+1)}=\frac{4a+1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B16a%5E%7B2%7D%2B8a%2B1%7D%7B12a%2B3%7D%3D%5Cfrac%7B%284a%2B1%29%5E%7B2%7D%7D%7B3%284a%2B1%29%7D%3D%5Cfrac%7B4a%2B1%7D%7B3%7D)