log₂2cos²π/12+log₂tgπ/12. Created by 7olesya. matematika-ru

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log₂2cos²π/12+log₂tgπ/12

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dtnth

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$log_2 2cos^2 \frac{\pi}{12}+log_2 tg \frac{\pi}{12}=\\\\ log_2 (2cos^2 \frac{\pi}{12}tg \frac{\pi}{12})=log_2 (2cos \frac{\pi}{12}sin \frac{\pi}{12})=\\\\log_2 sin(2*\frac{\pi}{12})=log_2 sin \frac{\pi}{6}=\\\\log_2 \frac{1}{2}=log_2 2^{-1}=-1$

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