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linar65
@linar65
August 2022
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12sin^2x-20sinx+7=0 полное решение
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mrevil96
Sinx=t
12t^2-20t+7=0
D=400-4*12*7=400-336=64
x1=8+20/24=7/6(не подходит)
x2=8-20/24=-3/6=-1/2
sinx=-1/2
x=7п/6+2пк
х=11п/6+2пк
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Answers & Comments
12t^2-20t+7=0
D=400-4*12*7=400-336=64
x1=8+20/24=7/6(не подходит)
x2=8-20/24=-3/6=-1/2
sinx=-1/2
x=7п/6+2пк
х=11п/6+2пк