[tex] {x}^{2} + 12x - 28 = 0 \\ x_1 x_2 = - 28 \\ x_1 + x_2 = - 12 \\ x_1 = - 14 \\ x_2 = 2[/tex]
Ответ: –14; 2
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[tex] {x}^{2} + 12x - 28 = 0 \\ x_1 x_2 = - 28 \\ x_1 + x_2 = - 12 \\ x_1 = - 14 \\ x_2 = 2[/tex]
Ответ: –14; 2