Ответ:
1)(1+2y)(1-2y+4y²)/(1-2y+4y²)+(2-y)(4+2y+y²)/[y((4+2y+y²)]=
=(1+2y)+(2-y)/y=(y+2y²+2-y)/y=(2y²+2)/4=2(y²+1)/y
2)(2+y)(4-2y+y²)/[y(4-2y+y²)]-(1-2y)(1+2y+4y²)/(1+2y+4y²)=
=(2+y)/y-(1-2y)=(2+y-y+2y²)/y=(2+2y²)/y=2(1+y²)/y
3)2(y²1)/y:2(1+y²)/y=1
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Объяснение:
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Ответ:
1)(1+2y)(1-2y+4y²)/(1-2y+4y²)+(2-y)(4+2y+y²)/[y((4+2y+y²)]=
=(1+2y)+(2-y)/y=(y+2y²+2-y)/y=(2y²+2)/4=2(y²+1)/y
2)(2+y)(4-2y+y²)/[y(4-2y+y²)]-(1-2y)(1+2y+4y²)/(1+2y+4y²)=
=(2+y)/y-(1-2y)=(2+y-y+2y²)/y=(2+2y²)/y=2(1+y²)/y
3)2(y²1)/y:2(1+y²)/y=1
Подробнее - на Znanija.com - znanija.com/task/24975909#readmore
Объяснение: