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Ответ:

дано

m(Zn) = 13 g

m(H2SO4) = 49 g

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V(H2) -?

Zn + H2SO4-->ZnSO4 + H2

M(Zn) = 65 g/mol

n(Zn) = m/M = 13 / 65 = 0.2 mol

M(H2SO4) = 98 g/mol

n(H2SO4) = m/M = 49 / 98 = 0.5 mol

n(Zn)  < n(H2SO4)

n(Zn) = n(H2) = 0.2mol

V(H2) = n * Vm = 0.2 * 22.4  = 4.48L

ответ 4.48 л

Объяснение: