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aidok20011
@aidok20011
September 2021
1
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1)3-√7\5-4х ≤0
2)2√2-5\6+4х <0
решите пожалуйста срочноо
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sedinalana
Verified answer
1
(3-√7)/(5-4x)≤0
3-√7>0⇒5-4x<0
4x>5
x>1,25
x∈(1,25;∞)
2
(2√2-5)/(6+4x)<0
2√2-5<0⇒6+4x>0
4x>-6
x>-1,5
x∈(-1,5;∞)
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Answers & Comments
Verified answer
1(3-√7)/(5-4x)≤0
3-√7>0⇒5-4x<0
4x>5
x>1,25
x∈(1,25;∞)
2
(2√2-5)/(6+4x)<0
2√2-5<0⇒6+4x>0
4x>-6
x>-1,5
x∈(-1,5;∞)