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veronika05
@veronika05
July 2022
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Помогите пожалуйста!!!!
В треугольнике ABC AC=BC, AB=10, sinA=12/13. Найдите высоту CH.
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Lenkasuslik
SinA = CH/AC => CH = 12AC/13
Пусть АС=х, тогда х^2=144x^2/169 + 25
25x^2/169 = 25
25x^2 = 169 * 25
x^2 = 169
x = 13
CH = 12 * 13/13 = 12.
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Answers & Comments
Пусть АС=х, тогда х^2=144x^2/169 + 25
25x^2/169 = 25
25x^2 = 169 * 25
x^2 = 169
x = 13
CH = 12 * 13/13 = 12.