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aigerim0407
@aigerim0407
July 2022
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1)Cos2a-? , если sina=-12/13 (p 2)sin2a-? , если sina=-12/13 (p
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wejde
Verified answer
Sina=-12/13
cos(2a)=cos²a-sin²a
sin²a=(-12/13)²=144/169
cos²a=1-sin²a=1-144/169=25/169
cos(2a)=25/169-144/169=-119/169
Ответ: cos(2a)=-119/169
1) sina=-12/13, a∈[π;3π/2]
sin(2a)=2sin(a)*cos(a)
cos²a=1-sin²a=1-144/169=25/169 ⇒ cos(a)=-5/13
sin(2a)=2*(-12/13)*(-5/13)=(2*5*12)/(13*13)=120/169
Ответ: sin(2a)=120/169
2) sina=-12/13, a∈[3π/2;2π]
sin(2a)=2sin(a)*cos(a)
cos²a=1-sin²a=1-144/169=25/169 ⇒ cos(a)=5/13
sin(2a)=2*(-12/13)*5/13=-(2*5*12)/(13*13)=-120/169
Ответ: sin(2a)=-120/169
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Verified answer
Sina=-12/13cos(2a)=cos²a-sin²a
sin²a=(-12/13)²=144/169
cos²a=1-sin²a=1-144/169=25/169
cos(2a)=25/169-144/169=-119/169
Ответ: cos(2a)=-119/169
1) sina=-12/13, a∈[π;3π/2]
sin(2a)=2sin(a)*cos(a)
cos²a=1-sin²a=1-144/169=25/169 ⇒ cos(a)=-5/13
sin(2a)=2*(-12/13)*(-5/13)=(2*5*12)/(13*13)=120/169
Ответ: sin(2a)=120/169
2) sina=-12/13, a∈[3π/2;2π]
sin(2a)=2sin(a)*cos(a)
cos²a=1-sin²a=1-144/169=25/169 ⇒ cos(a)=5/13
sin(2a)=2*(-12/13)*5/13=-(2*5*12)/(13*13)=-120/169
Ответ: sin(2a)=-120/169