131 132 133 134 135номера помогите срочно. Created by pupoka. algebra-ru

131 132 133 134 135номера помогите срочно...

pupoka @pupoka

June 2022 1 13 Report

131 132 133 134 135
номера помогите срочно

Answers & Comments

arsenlevadniy

Verified answer

133.
$\left \{ {{3-x>1,} \atop {x^2-9 \leq 9;}} \right. \left \{ {{-x>-2,} \atop {x^2-18 \leq 0;}} \right. \left \{ {{x$

$\left \{ {{x^2 \geq 4,} \atop {x-3>0;}} \right. \left \{ {{x^2 -4 \geq 0,} \atop {x>3;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {x>3;}} \right. \left \{ {{ \left [ {{x \leq -2,} \atop {x \geq 2,}} \right. } \atop {x>0;}} \right. \left [ {{ \left \{ {{x \leq -2,} \atop {x>3;}} \right. } \atop { \left \{ {{x \geq 2,} \atop {x>3;}} \right. }} \right. \left [ {{x\in\varnothing, } \atop { x>3; }} \right. \\ x>3, \\ x\in(3;+\infty).$

$\left \{ {{6x-x^2 \geq 0,} \atop {3-2x>x,}} \right. \left \{ {{-x(x-6) \geq 0,} \atop {-3x>-3,}} \right. \left \{ {{x(x-6) \leq 0,} \atop {x$
134.
$\left \{ {{x^2$

$\left \{ {{x^2 \geq 4,} \atop {(2-5x)^2 \geq 16;}} \right. \left \{ {{x^2-4 \geq 0,} \atop {(2-5x)^2-16 \geq 0;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {(18-5x)(-14-5x) \geq 0;}} \right. \left \{ {{(x+2)(x-2) \geq 0,} \atop {(x- \frac{18}{5})(x+ \frac{14}{5}) \geq 0;}} \right. \\ \left \{ {{ \left [ {{x \leq -2,} \atop {x \geq 2;}} \right. } \atop { \left [ {{x \leq -2,8,} \atop {x \geq 3,6;}} \right. }} \right. \left [ {{x \leq -2,8,} \atop {x \geq 3,6;}} \right.$
$x\in(-\infty;-2,8]\cup[3,6;+\infty).$

$\left \{ {{x^2$

135.
[tex] \left \{ {{(x-1)(2x-3)<0,} \atop {5(x- \frac{1}{5})(x+4)>0;}} \right. \left \{ {{(x-1)(x- \frac{3}{2} )<0,} \atop {(x- \frac{1}{5})(x+4)>0;}} \right. \left \{ {{1<x<1 \frac{1}{2},} \atop {\left [{ {{x<-4,} \atop {x> \frac{1}{5};}} \right. }} \right. \\1<x<1 \frac{1}{2}, \\x\in(1; \frac{1}{2}).[/tex]

[tex] \left \{ {{(x+3)(x-1) \geq 0,} \atop {(x+2)(2x-3) \leq 0;}} \right. \left \{ {{(x+3)(x-1) \geq 0,} \atop {(x+2)(x- \frac{3}{2}) \leq 0;}} \right. \left \{ {{ \left [ {{x \leq -3,} \atop {x \geq 1,}} \right. } \atop {-2 \leq x \leq 1 \frac{1}{2} ;}} \right. \\ 1 \leq x \leq 1 \frac{1}{2},\\ x\in[1; 1 \frac{1}{2}].[/tex]

arsenlevadniy 135.
[tex] \left \{ {{(x-1)(2x-3)<0,} \atop {5(x- \frac{1}{5})(x+4)>0;}} \right. \left \{ {{(x-1)(x- \frac{3}{2} )<0,} \atop {(x- \frac{1}{5})(x+4)>0;}} \right. \left \{ {{1<x<1 \frac{1}{2},} \atop {\left [{ {{x<-4,} \atop {x> \frac{1}{5};}} \right. }} \right. \\1<x<1 \frac{1}{2}, \\x\in(1; \frac{1}{2}).[/tex]

arsenlevadniy [tex] \left \{ {{(x+3)(x-1) \geq 0,} \atop {(x+2)(2x-3) \leq 0;}} \right. \left \{ {{(x+3)(x-1) \geq 0,} \atop {(x+2)(x- \frac{3}{2}) \leq 0;}} \right. \left \{ {{ \left [ {{x \leq -3,} \atop {x \geq 1,}} \right. } \atop {-2 \leq x \leq 1 \frac{1}{2} ;}} \right. \\ 1 \leq x \leq 1 \frac{1}{2},\\ x\in[1; 1 \frac{1}{2}].[/tex]

Answers & Comments

Verified answer

рекомендуемые вопросы

Helpful Links

Helpful Social