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R8A
@R8A
September 2021
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20
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КОМПЛЕКСНЫЕ ЧИСЛА.
Пример легкий, но я в этом не разбираюсь, поэтому требуется проверка.
Правильно ли решил?
(3-i)/(2+3i) + 2*(i-1)^3
У меня получилось -49+41i/13
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sedinalana
Verified answer
(3-i)/(2+3i)=(3-i)(2-3i)/[(2+3i)(2-3i)=(6-9i-2i-3)/(4+9)=(3-11i)/13=3/13-11/13*i
2*(i-1)³=-2i+6+6i-2=4+4i
(3-i)/(2+3i) + 2*(i-1)^3=3/13-11/13*i+4+4i=55/13+41/13*i
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Answers & Comments
Verified answer
(3-i)/(2+3i)=(3-i)(2-3i)/[(2+3i)(2-3i)=(6-9i-2i-3)/(4+9)=(3-11i)/13=3/13-11/13*i2*(i-1)³=-2i+6+6i-2=4+4i
(3-i)/(2+3i) + 2*(i-1)^3=3/13-11/13*i+4+4i=55/13+41/13*i