Ответ:вот
Пошаговое объяснение:
[tex]1)\;\;\frac{y+5}{110} =\frac{42}{660}\\\\660*(y+5)=42*110\\\\y+5=\frac{42*110}{660}\\\\y+5=\frac{42}{6}\\\\y+5=7 \\\\y=7 -5\\\\y=2.[/tex]
[tex]2)\;\;\frac{25}{17-y} =\frac{200}{56} \\\\200*(17-y)=25*56\\\\17-y=\frac{25*56}{200} \\\\17-y=\frac{56}{8} \\\\17-y=7\\\\y=17-7\\\\y=10.[/tex]
[tex]3)\;\;\frac{77}{800} =\frac{7,7}{y+53} \\\\77*(y+53)=800*7,7\\\\y+53=\frac{800*7,7}{77}\\\\ y+53=80\\\\y=80-53\\\\y=27.[/tex]
[tex]4)\;\;\frac{1}{1,8}=\frac{40-y}{32,4} \\\\1,8*(40-y)=32,4*1\\\\40-y=\frac{32,4}{1,8} \\\\40-y=18\\\\y=40-18\\\\y=22.[/tex]
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Answers & Comments
Ответ:вот
Пошаговое объяснение:
Verified answer
[tex]1)\;\;\frac{y+5}{110} =\frac{42}{660}\\\\660*(y+5)=42*110\\\\y+5=\frac{42*110}{660}\\\\y+5=\frac{42}{6}\\\\y+5=7 \\\\y=7 -5\\\\y=2.[/tex]
[tex]2)\;\;\frac{25}{17-y} =\frac{200}{56} \\\\200*(17-y)=25*56\\\\17-y=\frac{25*56}{200} \\\\17-y=\frac{56}{8} \\\\17-y=7\\\\y=17-7\\\\y=10.[/tex]
[tex]3)\;\;\frac{77}{800} =\frac{7,7}{y+53} \\\\77*(y+53)=800*7,7\\\\y+53=\frac{800*7,7}{77}\\\\ y+53=80\\\\y=80-53\\\\y=27.[/tex]
[tex]4)\;\;\frac{1}{1,8}=\frac{40-y}{32,4} \\\\1,8*(40-y)=32,4*1\\\\40-y=\frac{32,4}{1,8} \\\\40-y=18\\\\y=40-18\\\\y=22.[/tex]