Ответ: 1й
[tex] \frac{2x + 1}{x + 1} = x \\ 2x + 1 = {x}^{2} + x \\ {x}^{2} + x - 2x - 1 = 0 \\ {x}^{2} - x - 1 = 0[/tex]
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Ответ: 1й
[tex] \frac{2x + 1}{x + 1} = x \\ 2x + 1 = {x}^{2} + x \\ {x}^{2} + x - 2x - 1 = 0 \\ {x}^{2} - x - 1 = 0[/tex]