Дано:
W(H)=14,29%
Dпов(CxHy)=3,379
З-ти:
CxHy-?
Розв:
W(C)=100%-14,29%=85,71%
(85,71/12) : (14,29/1)
7 : 14,29
(7/7) : (14,29/7)
1 : 2 ---> CH2
M(CxHy)= 3,379×29=98
M(CH2)=14
98/14=7 ---> CH2×7= C7H14 гептен
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Дано:
W(H)=14,29%
Dпов(CxHy)=3,379
З-ти:
CxHy-?
Розв:
W(C)=100%-14,29%=85,71%
(85,71/12) : (14,29/1)
7 : 14,29
(7/7) : (14,29/7)
1 : 2 ---> CH2
M(CxHy)= 3,379×29=98
M(CH2)=14
98/14=7 ---> CH2×7= C7H14 гептен