Ответ:
a)
[tex] \frac{ {b}^{3} }{a} \div \frac{c}{b} = \frac{ {b}^{3} }{a} \times \frac{b}{c} = \frac{ {b}^{3} \times b}{ac} = \frac{ {b}^{3} \times {b}^{1} }{ac} = \frac{ {b}^{3 + 1} }{ac} = \frac{ {b}^{4} }{ac} [/tex]
б)
[tex] \frac{2x}{y} \div ( - m) = - \frac{2x}{y} \times \frac{1}{m} = - \frac{2x \times 1}{ym} = - \frac{2x}{my} [/tex]
в)
[tex] {( - \frac{ {a}^{9} }{4b}) }^{2} = {( \frac{ {a}^{9} }{4b} )}^{2} = \frac{ {( {a}^{9}) }^{2} }{ {(4b)}^{2} } = \frac{ {a}^{9 \times 2} }{ {4}^{2} {b}^{2} } = \frac{ {a}^{18} }{ {16b}^{2} } [/tex]
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Ответ:
a)
[tex] \frac{ {b}^{3} }{a} \div \frac{c}{b} = \frac{ {b}^{3} }{a} \times \frac{b}{c} = \frac{ {b}^{3} \times b}{ac} = \frac{ {b}^{3} \times {b}^{1} }{ac} = \frac{ {b}^{3 + 1} }{ac} = \frac{ {b}^{4} }{ac} [/tex]
б)
[tex] \frac{2x}{y} \div ( - m) = - \frac{2x}{y} \times \frac{1}{m} = - \frac{2x \times 1}{ym} = - \frac{2x}{my} [/tex]
в)
[tex] {( - \frac{ {a}^{9} }{4b}) }^{2} = {( \frac{ {a}^{9} }{4b} )}^{2} = \frac{ {( {a}^{9}) }^{2} }{ {(4b)}^{2} } = \frac{ {a}^{9 \times 2} }{ {4}^{2} {b}^{2} } = \frac{ {a}^{18} }{ {16b}^{2} } [/tex]