Объяснение:
1.
y=2cos7x-12x
y'=(2cos7x-12x)d/dx=(2cos7x)d/dx+(-12x)d/dx=
=2•(-sin7x•7)-12= -14sin7x-12
2.
y=sin(2x²-4)
y'=(sin(2x²-4))d/dx=(sing)d/dg•(2x²-4)d/dx=
=cosg•4x=cos(2x²-4)•4x=4xcos(2x²-4)
3.
y=√(-x²+5x-3)
y'=(√g)d/dg•(-x²+5x-3)d/dx=
=1/(2√g)•(-2x+5)=1/(2√(-x²+5x-3))•(-2x+5)=
=( -2x+5)/(2√(-x²+5x-3))
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Answers & Comments
Объяснение:
1.
y=2cos7x-12x
y'=(2cos7x-12x)d/dx=(2cos7x)d/dx+(-12x)d/dx=
=2•(-sin7x•7)-12= -14sin7x-12
2.
y=sin(2x²-4)
y'=(sin(2x²-4))d/dx=(sing)d/dg•(2x²-4)d/dx=
=cosg•4x=cos(2x²-4)•4x=4xcos(2x²-4)
3.
y=√(-x²+5x-3)
y'=(√g)d/dg•(-x²+5x-3)d/dx=
=1/(2√g)•(-2x+5)=1/(2√(-x²+5x-3))•(-2x+5)=
=( -2x+5)/(2√(-x²+5x-3))