Verified answer

Ответ:

a)

[tex](x +\frac{1}{7}) -\frac{4}{7} = \frac{2}{7}\\ x +\frac{1}{7}= \frac{2}{7}+\frac{4}{7}\\ x +\frac{1}{7}=\frac{6}{7}\\x = \frac{6}{7}-\frac{1}{7}\\x = \frac{5}{7}[/tex]

b)

[tex](x+2\frac{4}{11})-4\frac{7}{11} = 1\frac{6}{11}\\x+2\frac{4}{11}=4\frac{7}{11} + 1\frac{6}{11}\\x+2\frac{4}{11} = 5\frac{13}{11}\\x = 5\frac{13}{11}-2\frac{4}{11}\\x = 3\frac{9}{11}[/tex]

c)

[tex](x+1\frac{8}{9})-3\frac{7}{9} = 4\frac{4}{9} \\x+1\frac{8}{9} = 4\frac{4}{9}+3 \frac{7}{9}\\x+1\frac{8}{9} = 7\frac{11}{9}\\x=7\frac{11}{9}-1\frac{8}{9} \\x = 6\frac{3}{9}[/tex]

d)

[tex](2\frac{4}{13}+x)-9\frac{9}{13} = 7 \frac{7}{13}\\ 2\frac{4}{13}+x=9\frac{9}{13} + 7 \frac{7}{13}\\ 2\frac{4}{13}+x = 16\frac{16}{13}\\x = 16\frac{16}{13} - 2\frac{4}{13}\\x = 14\frac{12}{13}[/tex]