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kristinatrofim48
@kristinatrofim48
June 2023
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ТЕРМІНОВО ДАЮ 15 БАЛІВ
визначте об'єм 80 г метану
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tereskoanastasia143
Дано:
m(CH4)= 80г
V(CH4)-?
n= m/M n= V/Vm
Vm=22,4л/моль
m/M=V/Vm
V(CH4) = m*Vm/M
M(CH4)=12+4=16
V=80г * 22,4л/моль/16г/моль= 112л
1 votes
Thanks 1
s1k3pp
Verified answer
Дано:
m (CH4) = 80 г
————————
V (CH4) - ?
————————
Розв’язання:
V = n • Vm
n = m/M
M= 12+(1•4) =16 г/моль
n (CH4) = 80г:16 г/моль = 5 моль
V = 5 моль • 22,4 г/моль = 112 л
2 votes
Thanks 1
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Answers & Comments
m(CH4)= 80г
V(CH4)-?
n= m/M n= V/Vm
Vm=22,4л/моль
m/M=V/Vm
V(CH4) = m*Vm/M
M(CH4)=12+4=16
V=80г * 22,4л/моль/16г/моль= 112л
Verified answer
Дано:m (CH4) = 80 г
————————
V (CH4) - ?
————————
Розв’язання:
V = n • Vm
n = m/M
M= 12+(1•4) =16 г/моль
n (CH4) = 80г:16 г/моль = 5 моль
V = 5 моль • 22,4 г/моль = 112 л