Cu+ H2SO4≠
Zn+H2SO4=ZnSO4+H2
n(H2)=2,2/22.4=0.098
n(H2)/n(Zn)=1/1 ⇒n(Zn)=0.098
Mr(Zn)=65.4
m(Zn)=65.4*0.098=6.4
m(Cu)=15-6.4=8.6
ω(Cu)=8.6*100/15=57.3 процента
ω(Zn)=100-57.3=42.7 процента
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Cu+ H2SO4≠
Zn+H2SO4=ZnSO4+H2
n(H2)=2,2/22.4=0.098
n(H2)/n(Zn)=1/1 ⇒n(Zn)=0.098
Mr(Zn)=65.4
m(Zn)=65.4*0.098=6.4
m(Cu)=15-6.4=8.6
ω(Cu)=8.6*100/15=57.3 процента
ω(Zn)=100-57.3=42.7 процента