Са + 2Н2О → Са(ОН)2 + 1Н2
M (Ca) = 40 г/моль
4 / 40 = X / 1 × 22,4
X = 4 × 22,4 / 40 = 2,24 л
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Са + 2Н2О → Са(ОН)2 + 1Н2
M (Ca) = 40 г/моль
4 / 40 = X / 1 × 22,4
X = 4 × 22,4 / 40 = 2,24 л