Объяснение:
w(KOH)= m(KOH) / m(розчину) = (m(KOH)•w(KOH) / (m(Н2О) + m(KOH))
0.25= (150•0.4)/(x+150)
0.25(x+150)=150•0.4
0.25x+37,5= 60
0.25x=22,5
x= 90г води
w(KOH)= m(KOH) / m(розчину) = (m(KOH)•w(KOH)) / (m(Н2О) + m(KOH)) = (150•0.4)/(150+90)=60/240 = 0.25 (25%)
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Verified answer
Объяснение:
w(KOH)= m(KOH) / m(розчину) = (m(KOH)•w(KOH) / (m(Н2О) + m(KOH))
0.25= (150•0.4)/(x+150)
0.25(x+150)=150•0.4
0.25x+37,5= 60
0.25x=22,5
x= 90г води
w(KOH)= m(KOH) / m(розчину) = (m(KOH)•w(KOH)) / (m(Н2О) + m(KOH)) = (150•0.4)/(150+90)=60/240 = 0.25 (25%)