Ответ:

(√3)⁵

Объяснение:

[tex]\displaystyle \underline { b_3= b_1q^2=\sqrt{3} }\\\\b_1 = \frac{b_1q^2}{q^2} =\frac{\sqrt{3} }{q^2} \\\\b_2=b_1q=\frac{b_1q^2}{q} =\frac{\sqrt{3} }{q} \\\\\\b_3=\sqrt{3} \\\\b_4 = b_1q^3 = b_1q^2*q=\sqrt{3} *q\\\\\\b_5 = b_1*q^4 = b_1q^2*q^2= \sqrt{3} *q^2\\\\\\b_1*b_2*b_3*b_4*b_5=\frac{\sqrt{3} }{q^2} *\frac{\sqrt{3} }{q} *\sqrt{3} *q\sqrt{3} *q^2\sqrt{3} =(\sqrt{3} )^5[/tex]