Ответ:
Объяснение:
[tex]2. \\a^n-b^n+a^n^-^2*b^n^-^3-a^2b^3 =\\=a^2*a^n^-^2 -b^3*b^n^-^3+a^n^-^2*b^n^-^3-a^2b^3=\\=(a^2*a^n^-^2 +a^n^-^2*b^n^-^3) - (b^3*b^n^-^3+a^2b^3)=\\=a^n^-^2(a^2+b^n^-^3)-b^3(a^2+b^n^-^3) =\\=(a^2+b^n^-^3)(a^n^-^2-b^3)[/tex]
4.
[tex]10^n^-^1+2^2^n-5^n^-^1-2^n^+^1= (2*5)^n^-^1+(2^2^n-2^n^+^1)-5^n^-^1=\\=2^n^-^1*5^n^-^1+2^n*(2^n-2)-5^n^-^1= (2^n^-^1*5^n^-^1-5^n^-^1)+2^n^+^1*(2^n^-^1-1)=\\=5^n^-^1((2^n^-^1-1) +2^n^+^1*(2^n^-^1-1)=(2^n^-^1-1)(2^n^+^1+5^n^-^1)[/tex]
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Ответ:
Объяснение:
[tex]2. \\a^n-b^n+a^n^-^2*b^n^-^3-a^2b^3 =\\=a^2*a^n^-^2 -b^3*b^n^-^3+a^n^-^2*b^n^-^3-a^2b^3=\\=(a^2*a^n^-^2 +a^n^-^2*b^n^-^3) - (b^3*b^n^-^3+a^2b^3)=\\=a^n^-^2(a^2+b^n^-^3)-b^3(a^2+b^n^-^3) =\\=(a^2+b^n^-^3)(a^n^-^2-b^3)[/tex]
4.
[tex]10^n^-^1+2^2^n-5^n^-^1-2^n^+^1= (2*5)^n^-^1+(2^2^n-2^n^+^1)-5^n^-^1=\\=2^n^-^1*5^n^-^1+2^n*(2^n-2)-5^n^-^1= (2^n^-^1*5^n^-^1-5^n^-^1)+2^n^+^1*(2^n^-^1-1)=\\=5^n^-^1((2^n^-^1-1) +2^n^+^1*(2^n^-^1-1)=(2^n^-^1-1)(2^n^+^1+5^n^-^1)[/tex]