CaO + 2HCl --> CaCl2 + H2O
m(CaO) = 5.6г => n(CaO) = m/M = 5.6/56 = 0.1моль
n(CaCl2) = n(CaO) = 0.1моль
m(CaCl2) = n*M = 0.1*111 = 11.1г
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
CaO + 2HCl --> CaCl2 + H2O
m(CaO) = 5.6г => n(CaO) = m/M = 5.6/56 = 0.1моль
n(CaCl2) = n(CaO) = 0.1моль
m(CaCl2) = n*M = 0.1*111 = 11.1г