помогите объясните√2/5 × √42/11 × √77/15 -3,2√1целая 9/16. Created by sololo2. algebra-ru

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помогите объясните
√2/5 × √42/11 × √77/15 -3,2√1целая 9/16

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Banabanana

Verified answer

1) √ 2/5 * √ 42/11 * √ 77/15 = √ ( 2/5 * 42/11 * 77/15 ) = √ ( 588/75 ) = √ 7,84 =
= 2,8
2) 3,2 √ 1 9/16 = 3,2 √ 25/16 = 3,2 * 5/4 = 3,2 * 1,25 = 4
3) 2,8 - 4 = - 1,2
Ответ ( - 1,2 )

pri pomoshi soglasovannyh i nesoglasovannyh opredelenij rasprostranite nazyvnye p26532a140c1e80470d97bba30244558c 28624

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sololo2 July 2022 | 0 Ответы

pomogite nuzhno vypishit predlozhenie v takom poryadke 1opredelyonno lichnoe 2 neop

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5)=90+1,8=91,8...

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pri pomoshi soglasovannyh i nesoglasovannyh opredelenij rasprostranite nazyvnye p26532a140c1e80470d97bba30244558c 28624

pomogite nuzhno vypishit predlozhenie v takom poryadke 1opredelyonno lichnoe 2 neop

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