16a^3+54b^ разложить на множители
16a^3+54b^3=2({2a}^3+{3b}^3)=2(2a+3b)(4a^2-6ab+9b^2)
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16a^3+54b^3=2({2a}^3+{3b}^3)=2(2a+3b)(4a^2-6ab+9b^2)