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AlekseySlobodov @AlekseySlobodov

July 2022 1 6 Report

(с+2)во второй степени - (с+4)(с-4)
При c=3/16

Answers & Comments

andrisd

Verified answer

$(c+2)^2-(c+4)(c-4)=(c+2)(c+2)-(c^2-16)=$
$=c^2+4c+4-c^2+16=4c+20$

$\frac{3*4}{16} +20=20 \frac{3}{4}$

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