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2016Polya2016
@2016Polya2016
June 2022
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Добрый вечер!
Найдите периметр треугольника ABCABC, если AB=3 7/10см,BC=4 1/2см, AC=5 3/16см.
Заранее спасибо)
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chorobaktygul
Р=3 7/10 +4 1/2 +5 3/16=12целых(7·8+1·40 +3·5)/80=
12целых 111/80=13ц31/80
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Thanks 1
2016Polya2016
спасибо!)
NadDer
3 7\10 +4 1\2 + 5 3\16 =3 56\80 + 4 40\80 + 5 15\80 = 12 111\80 =
13 31\80
см - периметр АВС -в ОБЫКНОВ. дробях
3, 7+4,5+5,1875 =
14, 3875
см - периметр АВС - В ДЕС. дробях
0 votes
Thanks 1
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Answers & Comments
12целых 111/80=13ц31/80
3, 7+4,5+5,1875 = 14, 3875 см - периметр АВС - В ДЕС. дробях