16(x-1)(x+1)-(4x-7)²=0. Created by умнышка1. algebra-ru

16(x-1)(x+1)-(4x-7)²=0...

July 2022 1 10 Report

16(x-1)(x+1)-(4x-7)²=0

гюйс

16(х^2-1)-(16х^2-56х+49)=0
16х^2-16-16х^2+56х-49=0
56х=49+16
56х=65
х=65:56
х=1,16

0 votes Thanks 1

умнышка1 Спасибо))