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янка001
@янка001
July 2022
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16x^2=49 решить
2x^2-3x=0
x^2-2x-35=0
D или теорема Виета
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bitcoinmasterr
1)
2x²-3x=0
x(2x-3)=0
Либо :
х=0
х=1.5
2)
х²-2х-35=0
х=(2±√(4+140))/2
х=-5
х=7
1 votes
Thanks 2
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Answers & Comments
2x²-3x=0
x(2x-3)=0
Либо :
х=0
х=1.5
2)
х²-2х-35=0
х=(2±√(4+140))/2
х=-5
х=7