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katlabuga99
@katlabuga99
August 2022
1
18
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найдите корень уравнения log₅(13+x)=log₅ 8
(1/17)ˣ⁻¹ = 17ˣ
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oppression
Log₅(13+x)=log₅
8
13+х
≤0
х≤-13
log
₅(13+х)=log₅8, x
>-13
13+х=8
х=8-13
х=-5, х
>-13
Ответ: -5.
(
)ˣ⁻¹ = 17ˣ
(17
⁻¹)ˣ⁻¹=17ˣ
17
⁻⁽ˣ⁻¹⁾=17ˣ
17⁻ˣ⁺¹=17ˣ
-х+1=х
-х-х=-1
-2х=-1
х=0,5.
Ответ: 0,5.
2 votes
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Answers & Comments
13+х≤0
х≤-13
log₅(13+х)=log₅8, x>-13
13+х=8
х=8-13
х=-5, х>-13
Ответ: -5.
()ˣ⁻¹ = 17ˣ
(17⁻¹)ˣ⁻¹=17ˣ
17⁻⁽ˣ⁻¹⁾=17ˣ
17⁻ˣ⁺¹=17ˣ
-х+1=х
-х-х=-1
-2х=-1
х=0,5.
Ответ: 0,5.