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Маks5
@Маks5
August 2022
2
5
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Решите 4 класс. Уравнение
" 3/7 - ТРИ СЕДЬМЫЕ *** 1, 16/ 17 - ОДНА ЦЕЛАЯ ШЕСТНАДЦАТЬ СЕМНАДЦАТЫХ! "
а - 3/7 = 1, 16/17
а =
а =
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Answers & Comments
tatyanazubkova
А - 3/7 = 1, 16/17
а =1 16/17+3/7
а =1 112 /119+51/119
а=1 163/119
а=2 44/119
0 votes
Thanks 1
ChesNext
116 + 3 = 1 + 16 + 3 = 1 + 16·7 + 3·17 = 17717717·77·17
= 1 + 112 + 51 = 1 + 112 + 51 = 1 + 163 = 119119119119
= 1 + 44 + 1·119 = 1 + 1 + 44 = 244119119119
ChesNext
не то сори))
ChesNext
А=1,16/17+3/7
а=2,44/119
0 votes
Thanks 1
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Answers & Comments
а =1 16/17+3/7
а =1 112 /119+51/119
а=1 163/119
а=2 44/119
= 1 + 112 + 51 = 1 + 112 + 51 = 1 + 163 = 119119119119
= 1 + 44 + 1·119 = 1 + 1 + 44 = 244119119119
а=2,44/119